CVE Vulnerabilities

CVE-2011-0551

Cross-Site Request Forgery (CSRF)

Published: Aug 15, 2011 | Modified: Feb 07, 2013
CVSS 3.x
N/A
Source:
NVD
CVSS 2.x
6.8 MEDIUM
AV:N/AC:M/Au:N/C:P/I:P/A:P
RedHat/V2
RedHat/V3
Ubuntu

Cross-site request forgery (CSRF) vulnerability in the Web Interface in the Endpoint Protection Manager in Symantec Endpoint Protection (SEP) 11.0.600x through 11.0.6300 allows remote attackers to hijack the authentication of administrators for requests that create administrative accounts.

Weakness

The web application does not, or can not, sufficiently verify whether a well-formed, valid, consistent request was intentionally provided by the user who submitted the request.

Affected Software

Name Vendor Start Version End Version
Endpoint_protection Symantec 11.0.6300 11.0.6300
Endpoint_protection Symantec 11.0.6200.754 11.0.6200.754
Endpoint_protection Symantec 11.0.6100 11.0.6100
Endpoint_protection Symantec 11.0.6000 11.0.6000
Endpoint_protection Symantec 11.0.6200 11.0.6200

Potential Mitigations

  • Use a vetted library or framework that does not allow this weakness to occur or provides constructs that make this weakness easier to avoid.
  • For example, use anti-CSRF packages such as the OWASP CSRFGuard. [REF-330]
  • Another example is the ESAPI Session Management control, which includes a component for CSRF. [REF-45]
  • Use the “double-submitted cookie” method as described by Felten and Zeller:
  • When a user visits a site, the site should generate a pseudorandom value and set it as a cookie on the user’s machine. The site should require every form submission to include this value as a form value and also as a cookie value. When a POST request is sent to the site, the request should only be considered valid if the form value and the cookie value are the same.
  • Because of the same-origin policy, an attacker cannot read or modify the value stored in the cookie. To successfully submit a form on behalf of the user, the attacker would have to correctly guess the pseudorandom value. If the pseudorandom value is cryptographically strong, this will be prohibitively difficult.
  • This technique requires Javascript, so it may not work for browsers that have Javascript disabled. [REF-331]

References