CVE Vulnerabilities

CVE-2012-10015

Cross-Site Request Forgery (CSRF)

Published: May 31, 2023 | Modified: Apr 11, 2024
CVSS 3.x
8.8
HIGH
Source:
NVD
CVSS:3.1/AV:N/AC:L/PR:N/UI:R/S:U/C:H/I:H/A:H
CVSS 2.x
RedHat/V2
RedHat/V3
Ubuntu

A vulnerability was found in BestWebSoft Twitter Plugin up to 2.14 on WordPress. It has been classified as problematic. Affected is the function twttr_settings_page of the file twitter.php of the component Settings Page. The manipulation leads to cross-site request forgery. It is possible to launch the attack remotely. Upgrading to version 2.15 is able to address this issue. The patch is identified as a6d4659cbb2cbf18ccb0fb43549d5113d74e0146. It is recommended to upgrade the affected component. VDB-230154 is the identifier assigned to this vulnerability.

Weakness

The web application does not, or can not, sufficiently verify whether a well-formed, valid, consistent request was intentionally provided by the user who submitted the request.

Affected Software

Name Vendor Start Version End Version
Twitter Bestwebsoft * 2.15 (excluding)

Potential Mitigations

  • Use a vetted library or framework that does not allow this weakness to occur or provides constructs that make this weakness easier to avoid.
  • For example, use anti-CSRF packages such as the OWASP CSRFGuard. [REF-330]
  • Another example is the ESAPI Session Management control, which includes a component for CSRF. [REF-45]
  • Use the “double-submitted cookie” method as described by Felten and Zeller:
  • When a user visits a site, the site should generate a pseudorandom value and set it as a cookie on the user’s machine. The site should require every form submission to include this value as a form value and also as a cookie value. When a POST request is sent to the site, the request should only be considered valid if the form value and the cookie value are the same.
  • Because of the same-origin policy, an attacker cannot read or modify the value stored in the cookie. To successfully submit a form on behalf of the user, the attacker would have to correctly guess the pseudorandom value. If the pseudorandom value is cryptographically strong, this will be prohibitively difficult.
  • This technique requires Javascript, so it may not work for browsers that have Javascript disabled. [REF-331]

References