CVE Vulnerabilities


Cross-Site Request Forgery (CSRF)

Published: Feb 13, 2017 | Modified: May 20, 2018
CVSS 3.x
CVSS 2.x

An issue was discovered on Schneider Electric IONXXXX series power meters ION73XX series, ION75XX series, ION76XX series, ION8650 series, ION8800 series, and PM5XXX series. There is no CSRF Token generated to authenticate the user during a session. Successful exploitation of this vulnerability can allow unauthorized configuration changes to be made and saved.


The web application does not, or can not, sufficiently verify whether a well-formed, valid, consistent request was intentionally provided by the user who submitted the request.

Affected Software

Name Vendor Start Version End Version
Ion5000 Schneider-electric - (including) - (including)
Ion7300 Schneider-electric - (including) - (including)
Ion7500 Schneider-electric - (including) - (including)
Ion7600 Schneider-electric - (including) - (including)
Ion8650 Schneider-electric - (including) - (including)
Ion8800 Schneider-electric - (including) - (including)

Potential Mitigations

  • Use a vetted library or framework that does not allow this weakness to occur or provides constructs that make this weakness easier to avoid.
  • For example, use anti-CSRF packages such as the OWASP CSRFGuard. [REF-330]
  • Another example is the ESAPI Session Management control, which includes a component for CSRF. [REF-45]
  • Use the “double-submitted cookie” method as described by Felten and Zeller:
  • When a user visits a site, the site should generate a pseudorandom value and set it as a cookie on the user’s machine. The site should require every form submission to include this value as a form value and also as a cookie value. When a POST request is sent to the site, the request should only be considered valid if the form value and the cookie value are the same.
  • Because of the same-origin policy, an attacker cannot read or modify the value stored in the cookie. To successfully submit a form on behalf of the user, the attacker would have to correctly guess the pseudorandom value. If the pseudorandom value is cryptographically strong, this will be prohibitively difficult.
  • This technique requires Javascript, so it may not work for browsers that have Javascript disabled. [REF-331]