CVE Vulnerabilities

CVE-2017-18781

Cross-Site Request Forgery (CSRF)

Published: Apr 22, 2020 | Modified: Apr 24, 2020
CVSS 3.x
8.8
HIGH
Source:
NVD
CVSS:3.1/AV:N/AC:L/PR:N/UI:R/S:U/C:H/I:H/A:H
CVSS 2.x
6.8 MEDIUM
AV:N/AC:M/Au:N/C:P/I:P/A:P
RedHat/V2
RedHat/V3
Ubuntu

Certain NETGEAR devices are affected by CSRF. This affects D6200 before 1.1.00.24, D7000 before 1.0.1.52, JNR1010v2 before 1.1.0.44, JWNR2010v5 before 1.1.0.44, JR6150 before 1.0.1.12, PR2000 before 1.0.0.20, R6020 before 1.0.0.26, R6050 before 1.0.1.12, R6080 before 1.0.0.26, R6120 before 1.0.0.36, R6220 before 1.1.0.60, R6700v2 before 1.2.0.12, R6800 before 1.2.0.12, R6900v2 before 1.2.0.12, WNDR3700v5 before 1.1.0.50, WNR1000v4 before 1.1.0.44, WNR2020 before 1.1.0.44, and WNR2050 before 1.1.0.44.

Weakness

The web application does not, or can not, sufficiently verify whether a well-formed, valid, consistent request was intentionally provided by the user who submitted the request.

Affected Software

Name Vendor Start Version End Version
D6200_firmware Netgear * 1.1.00.24 (excluding)

Potential Mitigations

  • Use a vetted library or framework that does not allow this weakness to occur or provides constructs that make this weakness easier to avoid.
  • For example, use anti-CSRF packages such as the OWASP CSRFGuard. [REF-330]
  • Another example is the ESAPI Session Management control, which includes a component for CSRF. [REF-45]
  • Use the “double-submitted cookie” method as described by Felten and Zeller:
  • When a user visits a site, the site should generate a pseudorandom value and set it as a cookie on the user’s machine. The site should require every form submission to include this value as a form value and also as a cookie value. When a POST request is sent to the site, the request should only be considered valid if the form value and the cookie value are the same.
  • Because of the same-origin policy, an attacker cannot read or modify the value stored in the cookie. To successfully submit a form on behalf of the user, the attacker would have to correctly guess the pseudorandom value. If the pseudorandom value is cryptographically strong, this will be prohibitively difficult.
  • This technique requires Javascript, so it may not work for browsers that have Javascript disabled. [REF-331]

References