XWiki Platform is vulnerable to Cross-Site Request Forgery (CSRF) that may allow attackers to delete or rename tags without needing any confirmation. The problem has been patched in XWiki 13.10.7, 14.4.1 and 14.5RC1. Workarounds: Its possible to patch existing instances directly by editing the page Main.Tags and add this kind of check, in the code for renaming and for deleting: #if (!$services.csrf.isTokenValid($request.get(form_token))) #set ($discard = $response.sendError(401, Wrong CSRF token)) #end
Weakness
The web application does not, or can not, sufficiently verify whether a well-formed, valid, consistent request was intentionally provided by the user who submitted the request.
Affected Software
| Name |
Vendor |
Start Version |
End Version |
| Xwiki |
Xwiki |
3.2 (excluding) |
13.10.7 (excluding) |
| Xwiki |
Xwiki |
3.2-milestone2 (including) |
3.2-milestone2 (including) |
| Xwiki |
Xwiki |
3.2-milestone3 (including) |
3.2-milestone3 (including) |
| Xwiki |
Xwiki |
14.4 (including) |
14.4 (including) |
Potential Mitigations
- Use a vetted library or framework that does not allow this weakness to occur or provides constructs that make this weakness easier to avoid.
- For example, use anti-CSRF packages such as the OWASP CSRFGuard. [REF-330]
- Another example is the ESAPI Session Management control, which includes a component for CSRF. [REF-45]
- Use the “double-submitted cookie” method as described by Felten and Zeller:
- When a user visits a site, the site should generate a pseudorandom value and set it as a cookie on the user’s machine. The site should require every form submission to include this value as a form value and also as a cookie value. When a POST request is sent to the site, the request should only be considered valid if the form value and the cookie value are the same.
- Because of the same-origin policy, an attacker cannot read or modify the value stored in the cookie. To successfully submit a form on behalf of the user, the attacker would have to correctly guess the pseudorandom value. If the pseudorandom value is cryptographically strong, this will be prohibitively difficult.
- This technique requires Javascript, so it may not work for browsers that have Javascript disabled. [REF-331]
References