In multiple locations, there is a possible way to corrupt memory due to a double free. This could lead to local escalation of privilege with no additional execution privileges needed. User interaction is not needed for exploitation.
The product calls free() twice on the same memory address, potentially leading to modification of unexpected memory locations.
| Name | Vendor | Start Version | End Version |
|---|---|---|---|
| Android | 14.0 (including) | 14.0 (including) |