CVE Vulnerabilities

CVE-2025-20322

Cross-Site Request Forgery (CSRF)

Published: Jul 07, 2025 | Modified: Jul 07, 2025
CVSS 3.x
N/A
Source:
NVD
CVSS 2.x
RedHat/V2
RedHat/V3
Ubuntu

In Splunk Enterprise versions below 9.4.3, 9.3.5, 9.2.7, and 9.1.10, and Splunk Cloud Platform versions below 9.3.2411.104, 9.3.2408.113, and 9.2.2406.119, an unauthenticated attacker could send a specially-crafted SPL search command that could trigger a rolling restart in the Search Head Cluster through a Cross-Site Request Forgery (CSRF), potentially leading to a denial of service (DoS).The vulnerability requires the attacker to phish the administrator-level victim by tricking them into initiating a request within their browser. The attacker should not be able to exploit the vulnerability at will.See How rolling restart works for more information.

Weakness

The web application does not, or can not, sufficiently verify whether a well-formed, valid, consistent request was intentionally provided by the user who submitted the request.

Potential Mitigations

  • Use a vetted library or framework that does not allow this weakness to occur or provides constructs that make this weakness easier to avoid.
  • For example, use anti-CSRF packages such as the OWASP CSRFGuard. [REF-330]
  • Another example is the ESAPI Session Management control, which includes a component for CSRF. [REF-45]
  • Use the “double-submitted cookie” method as described by Felten and Zeller:
  • When a user visits a site, the site should generate a pseudorandom value and set it as a cookie on the user’s machine. The site should require every form submission to include this value as a form value and also as a cookie value. When a POST request is sent to the site, the request should only be considered valid if the form value and the cookie value are the same.
  • Because of the same-origin policy, an attacker cannot read or modify the value stored in the cookie. To successfully submit a form on behalf of the user, the attacker would have to correctly guess the pseudorandom value. If the pseudorandom value is cryptographically strong, this will be prohibitively difficult.
  • This technique requires Javascript, so it may not work for browsers that have Javascript disabled. [REF-331]

References